Optimal. Leaf size=227 \[ a^4 A x+\frac {a b \left (4 a^2 (2 A+C)+b^2 (4 A+3 C)\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {\left (6 a^4 C+2 b^4 (5 A+4 C)+a^2 b^2 (85 A+56 C)\right ) \tan (c+d x)}{15 d}+\frac {a b \left (40 A b^2+6 a^2 C+29 b^2 C\right ) \sec (c+d x) \tan (c+d x)}{30 d}+\frac {\left (3 a^2 C+b^2 (5 A+4 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{15 d}+\frac {a C (a+b \sec (c+d x))^3 \tan (c+d x)}{5 d}+\frac {C (a+b \sec (c+d x))^4 \tan (c+d x)}{5 d} \]
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Rubi [A]
time = 0.33, antiderivative size = 227, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 6, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.240, Rules used = {4142, 4141,
4133, 3855, 3852, 8} \begin {gather*} a^4 A x+\frac {a b \left (4 a^2 (2 A+C)+b^2 (4 A+3 C)\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {a b \left (6 a^2 C+40 A b^2+29 b^2 C\right ) \tan (c+d x) \sec (c+d x)}{30 d}+\frac {\left (3 a^2 C+b^2 (5 A+4 C)\right ) \tan (c+d x) (a+b \sec (c+d x))^2}{15 d}+\frac {\left (6 a^4 C+a^2 b^2 (85 A+56 C)+2 b^4 (5 A+4 C)\right ) \tan (c+d x)}{15 d}+\frac {a C \tan (c+d x) (a+b \sec (c+d x))^3}{5 d}+\frac {C \tan (c+d x) (a+b \sec (c+d x))^4}{5 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 3852
Rule 3855
Rule 4133
Rule 4141
Rule 4142
Rubi steps
\begin {align*} \int (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx &=\frac {C (a+b \sec (c+d x))^4 \tan (c+d x)}{5 d}+\frac {1}{5} \int (a+b \sec (c+d x))^3 \left (5 a A+b (5 A+4 C) \sec (c+d x)+4 a C \sec ^2(c+d x)\right ) \, dx\\ &=\frac {a C (a+b \sec (c+d x))^3 \tan (c+d x)}{5 d}+\frac {C (a+b \sec (c+d x))^4 \tan (c+d x)}{5 d}+\frac {1}{20} \int (a+b \sec (c+d x))^2 \left (20 a^2 A+4 a b (10 A+7 C) \sec (c+d x)+4 \left (3 a^2 C+b^2 (5 A+4 C)\right ) \sec ^2(c+d x)\right ) \, dx\\ &=\frac {\left (3 a^2 C+b^2 (5 A+4 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{15 d}+\frac {a C (a+b \sec (c+d x))^3 \tan (c+d x)}{5 d}+\frac {C (a+b \sec (c+d x))^4 \tan (c+d x)}{5 d}+\frac {1}{60} \int (a+b \sec (c+d x)) \left (60 a^3 A+4 b \left (9 a^2 (5 A+3 C)+2 b^2 (5 A+4 C)\right ) \sec (c+d x)+4 a \left (40 A b^2+6 a^2 C+29 b^2 C\right ) \sec ^2(c+d x)\right ) \, dx\\ &=\frac {a b \left (40 A b^2+6 a^2 C+29 b^2 C\right ) \sec (c+d x) \tan (c+d x)}{30 d}+\frac {\left (3 a^2 C+b^2 (5 A+4 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{15 d}+\frac {a C (a+b \sec (c+d x))^3 \tan (c+d x)}{5 d}+\frac {C (a+b \sec (c+d x))^4 \tan (c+d x)}{5 d}+\frac {1}{120} \int \left (120 a^4 A+60 a b \left (4 a^2 (2 A+C)+b^2 (4 A+3 C)\right ) \sec (c+d x)+8 \left (6 a^4 C+2 b^4 (5 A+4 C)+a^2 b^2 (85 A+56 C)\right ) \sec ^2(c+d x)\right ) \, dx\\ &=a^4 A x+\frac {a b \left (40 A b^2+6 a^2 C+29 b^2 C\right ) \sec (c+d x) \tan (c+d x)}{30 d}+\frac {\left (3 a^2 C+b^2 (5 A+4 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{15 d}+\frac {a C (a+b \sec (c+d x))^3 \tan (c+d x)}{5 d}+\frac {C (a+b \sec (c+d x))^4 \tan (c+d x)}{5 d}+\frac {1}{2} \left (a b \left (4 a^2 (2 A+C)+b^2 (4 A+3 C)\right )\right ) \int \sec (c+d x) \, dx+\frac {1}{15} \left (6 a^4 C+2 b^4 (5 A+4 C)+a^2 b^2 (85 A+56 C)\right ) \int \sec ^2(c+d x) \, dx\\ &=a^4 A x+\frac {a b \left (4 a^2 (2 A+C)+b^2 (4 A+3 C)\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {a b \left (40 A b^2+6 a^2 C+29 b^2 C\right ) \sec (c+d x) \tan (c+d x)}{30 d}+\frac {\left (3 a^2 C+b^2 (5 A+4 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{15 d}+\frac {a C (a+b \sec (c+d x))^3 \tan (c+d x)}{5 d}+\frac {C (a+b \sec (c+d x))^4 \tan (c+d x)}{5 d}-\frac {\left (6 a^4 C+2 b^4 (5 A+4 C)+a^2 b^2 (85 A+56 C)\right ) \text {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{15 d}\\ &=a^4 A x+\frac {a b \left (4 a^2 (2 A+C)+b^2 (4 A+3 C)\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {\left (6 a^4 C+2 b^4 (5 A+4 C)+a^2 b^2 (85 A+56 C)\right ) \tan (c+d x)}{15 d}+\frac {a b \left (40 A b^2+6 a^2 C+29 b^2 C\right ) \sec (c+d x) \tan (c+d x)}{30 d}+\frac {\left (3 a^2 C+b^2 (5 A+4 C)\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{15 d}+\frac {a C (a+b \sec (c+d x))^3 \tan (c+d x)}{5 d}+\frac {C (a+b \sec (c+d x))^4 \tan (c+d x)}{5 d}\\ \end {align*}
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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(503\) vs. \(2(227)=454\).
time = 2.54, size = 503, normalized size = 2.22 \begin {gather*} \frac {\left (C+A \cos ^2(c+d x)\right ) \sec ^5(c+d x) \left (150 a^4 A (c+d x) \cos (c+d x)+75 a^4 A (c+d x) \cos (3 (c+d x))+15 a^4 A c \cos (5 (c+d x))+15 a^4 A d x \cos (5 (c+d x))-120 a b \left (4 a^2 (2 A+C)+b^2 (4 A+3 C)\right ) \cos ^5(c+d x) \left (\log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-\log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )\right )+180 a^2 A b^2 \sin (c+d x)+40 A b^4 \sin (c+d x)+30 a^4 C \sin (c+d x)+240 a^2 b^2 C \sin (c+d x)+80 b^4 C \sin (c+d x)+120 a A b^3 \sin (2 (c+d x))+120 a^3 b C \sin (2 (c+d x))+210 a b^3 C \sin (2 (c+d x))+270 a^2 A b^2 \sin (3 (c+d x))+50 A b^4 \sin (3 (c+d x))+45 a^4 C \sin (3 (c+d x))+300 a^2 b^2 C \sin (3 (c+d x))+40 b^4 C \sin (3 (c+d x))+60 a A b^3 \sin (4 (c+d x))+60 a^3 b C \sin (4 (c+d x))+45 a b^3 C \sin (4 (c+d x))+90 a^2 A b^2 \sin (5 (c+d x))+10 A b^4 \sin (5 (c+d x))+15 a^4 C \sin (5 (c+d x))+60 a^2 b^2 C \sin (5 (c+d x))+8 b^4 C \sin (5 (c+d x))\right )}{120 d (A+2 C+A \cos (2 (c+d x)))} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.13, size = 275, normalized size = 1.21 Too large to display
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.29, size = 318, normalized size = 1.40 \begin {gather*} \frac {60 \, {\left (d x + c\right )} A a^{4} + 120 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} C a^{2} b^{2} + 20 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} A b^{4} + 4 \, {\left (3 \, \tan \left (d x + c\right )^{5} + 10 \, \tan \left (d x + c\right )^{3} + 15 \, \tan \left (d x + c\right )\right )} C b^{4} - 15 \, C a b^{3} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 60 \, C a^{3} b {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 60 \, A a b^{3} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 240 \, A a^{3} b \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 60 \, C a^{4} \tan \left (d x + c\right ) + 360 \, A a^{2} b^{2} \tan \left (d x + c\right )}{60 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 2.50, size = 251, normalized size = 1.11 \begin {gather*} \frac {60 \, A a^{4} d x \cos \left (d x + c\right )^{5} + 15 \, {\left (4 \, {\left (2 \, A + C\right )} a^{3} b + {\left (4 \, A + 3 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{5} \log \left (\sin \left (d x + c\right ) + 1\right ) - 15 \, {\left (4 \, {\left (2 \, A + C\right )} a^{3} b + {\left (4 \, A + 3 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{5} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (30 \, C a b^{3} \cos \left (d x + c\right ) + 6 \, C b^{4} + 2 \, {\left (15 \, C a^{4} + 30 \, {\left (3 \, A + 2 \, C\right )} a^{2} b^{2} + 2 \, {\left (5 \, A + 4 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{4} + 15 \, {\left (4 \, C a^{3} b + {\left (4 \, A + 3 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{3} + 2 \, {\left (30 \, C a^{2} b^{2} + {\left (5 \, A + 4 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{60 \, d \cos \left (d x + c\right )^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (A + C \sec ^{2}{\left (c + d x \right )}\right ) \left (a + b \sec {\left (c + d x \right )}\right )^{4}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 778 vs.
\(2 (215) = 430\).
time = 0.53, size = 778, normalized size = 3.43 \begin {gather*} \frac {30 \, {\left (d x + c\right )} A a^{4} + 15 \, {\left (8 \, A a^{3} b + 4 \, C a^{3} b + 4 \, A a b^{3} + 3 \, C a b^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 15 \, {\left (8 \, A a^{3} b + 4 \, C a^{3} b + 4 \, A a b^{3} + 3 \, C a b^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) - \frac {2 \, {\left (30 \, C a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 60 \, C a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 180 \, A a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 180 \, C a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 60 \, A a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 75 \, C a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 30 \, A b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 30 \, C b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 120 \, C a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 120 \, C a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 720 \, A a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 480 \, C a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 120 \, A a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 30 \, C a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 80 \, A b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 40 \, C b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 180 \, C a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 1080 \, A a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 600 \, C a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 100 \, A b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 116 \, C b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 120 \, C a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 120 \, C a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 720 \, A a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 480 \, C a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 120 \, A a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 30 \, C a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 80 \, A b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 40 \, C b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 30 \, C a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 60 \, C a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 180 \, A a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 180 \, C a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 60 \, A a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 75 \, C a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 30 \, A b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 30 \, C b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{5}}}{30 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 6.51, size = 1738, normalized size = 7.66 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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